A triene is treated with ozone followed by zi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Reductive ozonolysis of a triene involves the cleavage of all three double bonds. Given products are: $1$. $HCHO$ (Formaldehyde) $2$. $OHC-CH_2-CH

Vedclass · Accepted Answer

$1-$vinylcyclohex$-1,3-$diene

Vedclass · Answer

(A) Reductive ozonolysis of a triene involves the cleavage of all three double bonds. Given products are: $1$. $HCHO$ (Formaldehyde) $2$. $OHC-CH_2-CHO$ (Malonaldehyde) $3$. $OHC-CH_2-CO-CHO$ ($2$-oxomalonaldehyde) Analyzing the structure of $1-$vinylcyclohex$-1,3-$diene: It has three double bonds: one in the vinyl group and two in the ring. Cleavage of the vinyl double bond gives $HCHO$ and a formyl group attached to the ring. Cleavage of the ring double bonds at positions $1$ and $3$ results in the formation of the observed dicarbonyl and tricarbonyl fragments. Thus,the triene is $1-$vinylcyclohex$-1,3-$diene.

$A$ triene is treated with ozone followed by zinc in acetic acid to give the following three products. What is the structure of the triene?

Similar Questions

The major product of the following reaction contains $.....$ bromine atom$(s)$.

The correct statement is

Petroleum refining is:

$1, 2-$dibromocyclooctane $\xrightarrow[\substack{\text{(ii) } NaNH_2 \\ \text{(iii) } Hg^{2+} / H^{+} \\ \text{(iv) } Zn-Hg / H^{+}}]{\text{(i) } KOH \text{ (alc.) }} \underset{\text{(Major product)}}{P}$. $P$ is

Arrange benzene,$n$-hexane and ethyne in decreasing order of their acidic behaviour.

Vedclass Test Series

Exam Paper Generator

Online Exam Module